Question

I’m not sure how to solve a problem like this and also state the excluded values.

(4n/n+4)-(5n/n-3)

Answer 1

After solving, we get the final expression as:
`\frac{-n^(2)-32n {} }{(n+4)(n-3)}`

Explanation:

Given:

`(4n)/(n+4) - (5n)/(n-3)`

=
`(4n)/(n+4) - (5n)/(n-3)`

Now taking L.C.M,

=
`(4n(n-3)-5n(n+4))/((n+4)(n-3))`

Simplify the equation in numerator,

=
`\frac{4n^(2)-12n-5n^2 {-20n} }{(n+4)(n-3)}`

= =
`\frac{-n^(2)-32n {} }{(n+4)(n-3)}`

Thus, this is the required solution:
`\frac{-n^(2)-32n {} }{(n+4)(n-3)}`