Question

Genes A, B, and C are linked on a chromosome and found in the order A-B-C. Genes A and B recombine with a frequency of 8%, and genes B and C recombine at a frequency of 24%. For the cross a + b + c /abc + × abc / abc, predict the frequency of progeny. Assume interference is zero.

Predict the frequency of a+b+c progeny.

Can someone can please explain this step by step?

Answer 1

11.02

Step-by-step explanation:

Predict the frequency of a+b+c progeny = 11.02

Step by step Explanation for all genes

a---8%----b---------24%--------c

Double cross overs = (RF at first locus × RF at second locus)/100

= 8 × 24 /100 =1.92

Double cross over progeny;

a b+ c =0.96

a+ b c+= 0.96

single cross over progeny;

RF = 8

SCO at first locus progeny= 8 -DCO progeny= 8- 1.92 = 6.08

a b+ c+= 3.04

a+ b c= 3.04

single cross over at second locus progeny---

RF = 24

SCO at second locus progeny= 24-DCO progeny= 24 - 1.92 = 22.02

abc+= 11.02;

a+b+c = 11.02;

Total recombinants = 1.92 + 6.08 + 22.02 = 30.02

Total nonrecombinants are = 100 - 30.02 = 69.98

abc = 34.99

a+b+c+ = 34.99.