Answer:
N(24, 3.46)
Explanation:
We are given the following in the question:
Percentage of family homes having front poach = 50%
![p = 50\% = 0.50](https://img.qammunity.org/2021/formulas/mathematics/college/oxqrbe5y47tla3ssocmecrkbr4lth564w9.png)
Sample size, n = 48
Normal approximation to the given distribution:
![\mu = np = 48(0.50) = 24](https://img.qammunity.org/2021/formulas/mathematics/college/d8mgjschugoijt1zg80k9uh5nwbd5quay8.png)
![\sigma = √(np(1-p)) = √(48(0.50)(1-0.50)) = 3.46](https://img.qammunity.org/2021/formulas/mathematics/college/j5dz5o13lrgyr79c5z30rfjwolbaqrke9t.png)
Thus, the distribution of single family homes is best approximated by the normal distribution N(24, 3.46) where mean is 24 and standard deviation is 3.46