Question

If the jet is moving at a speed of 1250 km/h at the lowest point of the loop, determine the minimum radius of the circle so that the centripetal acceleration at the lowest point does not exceed 6.5 g's.

Answer 1

The minimum radius of the circle is 1892.75 meters

Step-by-step explanation:

Speed of the jet, v = 1250 km/h = 347.23 m/s

We need to find the minimum radius of the circle so that the centripetal acceleration at the lowest point does not exceed 6.5 g.

The centripetal acceleration is given by :

`a=(v^2)/(r)\\\\r=(v^2)/(a)\\\\r=((347.23)^2)/(6.5* 9.8)\\\\r=1892.75\ m`

So, the minimum radius of the circle is 1892.75 meters. Hence, this is the required solution.