Question

The support at the left end of the beam will fail if the moment about A of the 15-kN force F exceeds 18 kN-m. Based on this criterion, what is the largest allowable length of the beam

Answer 1

2.4 m

Step-by-step explanation:

We are given that

Maximum moment about A=18 kN m

Force=15 KN

`\theta=30^(\circ)`

We have to find the largest allowable length of the beam

Let larges length of beam=L

Moment about A

M=
`LFsin 30=L(15)sin 30=7.5 LkN m`

According to question

`M=M_(max)`

`7.5 L=18`

`L=(18)/(7.5)=2.4 m`

Hence, the largest length of the beam=2.4 m