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LINK Relating Volume and Absolute Temperature

ABOUT IT
Temperature (K)
Volume (L)
How well can you apply Charles's law to this
sample of gas that experiences changes in
pressure and volume? Assume that pressure and
number of moles of gas are constant in this
problem
295
10
250
Using the first volume and temperature reading on
the table as V1 and T1, solve for the unknown
values in the table below. Remember to use the
rules of significant figures when entering your
numeric response
325
0.75
DONE

User Jahn
by
4.1k points

1 Answer

4 votes

The volume is reduced to 8.5 L.

Step-by-step explanation:

According to Charles law, the gases has the tendency to expand on heating, and so the volume of the gases increases on increasing the temperature which is measured in Kelvin, and also the volume and temperature are in direct proportion.

Given that:

V1 = Volume 1 = 10 L

T1 = Temperature 1 = 295 K

V2 = ?

T2 = Temperature 2= 250 K

Now Charles law can be mathematically expressed as,


$(V1)/(T1) = (V2)/(T2)

We can rearrange the equation to find V2 as,


$ V2= (V1* T2)/(T1)


$ V2 = (10 L * 250 K)/(295 K) = 8.5 L

Thus we obtain the volume V2 = 8.5 L which is low when compared to Volume 1 so we can conclude that the volume has reduced

User Tyronn
by
4.8k points