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A series RCL circuit includes a resistance of 286, an inductive reactance of 486, and a capacitive reactance of 320. The current in the circuit is 0.273 A. What is the voltage of the generator? Note: The ac current and voltage are rms values and power is an average value unless indicated otherwise.

User Samn
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Answer:

Step-by-step explanation:

Resistance, R = 286 Ohm

Inductive reactance, XL = 486 ohm

Capacitive reactance, Xc = 320 ohm

Irms = 0.273 A

Let Z be the impedance of the circuit.


Z = \sqrt{R^(2)+\left ( X_(L)-X_(C) \right )^(2)}


Z = \sqrt{286^(2)+\left (486 - 320 \right )^(2)}

Z = 330.7 ohm

Let v be the voltage.

V = I rms x Z

V = 0.273 x 330.7

V = 90.3 V

User Bfmags
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