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An astronomical telescope has its two lenses spaced 82.1 cmcm apart. If the objective lens has a focal length of 78.0 cmcm , what is the magnification of this telescope
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An astronomical telescope has its two lenses spaced 82.1 cmcm apart. If the objective lens has a focal length of 78.0 cmcm , what is the magnification of this telescope

User Gaessaki
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1 Answer

3 votes

Answer:

19.02

Step-by-step explanation:

Let Fo = focal length of the objective and

Fe = focal length of the eyepiece

Fo + Fe = 82.1 cm where Fo = 78.0 cm

Fe = 82.1 cm - 78.0cm = 4.1 cm

magnification = Fo / Fe = 78 / 4.1 = 19.02

User Pezo
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