Question

For the reaction 2 H 2 O ( g ) − ⇀ ↽ − 2 H 2 ( g ) + O 2 ( g ) the equilibrium concentrations were found to be [ H 2 O ] = 0.250 M , [ H 2 ] = 0.330 M , and [ O 2 ] = 0.800 M . What is the equilibrium constant for this reaction?

Answer 1

Answer: The equilibrium constant for the given reaction is 4.224

Step-by-step explanation:

We are given:

Equilibrium concentration of water = 0.250 M

Equilibrium concentration of hydrogen gas = 0.330 M

Equilibrium concentration of oxygen gas = 0.800 M

For the given chemical reaction:

`2H_2O(g)\rightleftharpoons H_2(g)+O_2(g)`

The expression of
`K_(eq)` for above reaction follows:

`K_(eq)=([H_2][O_2])/([H_2O]^2)`

Putting values in above expression, we get:

`K_(eq)=(0.330* 0.800)/((0.250)^2)\\\\K_(eq)=4.224`

Hence, the equilibrium constant for the given reaction is 4.224