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A bag contains 3 red marbles 4 blue marbles and 7 Green marbles if two marbles are drawn out of the bag what is the probability to the nearest 1000th that both marbles drawn will be red

1 Answer

3 votes

Answer:

0.368

Explanation:

Number of red marbles= 3

Number of blue marbles= 4

Number of green marbles= 7

Total number of marbles= 3+4+7= 14

Let the first ball is taken out to be red

P(R)=
(3)/(14)

than again a second ball is drawn, number of balls left= 14-1=13

Number of red= 2

P(R)=
(2)/(13)

Total probability=
(3)/(14)+
(2)/(13)

Total probability= 0.368

Hence, the correct answer is 0.368

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