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When a bat uses echolocation to determine the distance to an insect, it sends out a sound wave and waits to see how long the sound takes to echo back. Suppose now that a bat hears its echo 0.06 LaTeX:
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When a bat uses echolocation to determine the distance to an insect, it sends out a sound wave and waits to see how long the sound takes to echo back. Suppose now that a bat hears its echo 0.06 LaTeX: ss after it emitted the sound. If the speed of sound is 344.9 LaTeX: \frac{m}{s}m s, how far away is the insect in meters?

User Zastrowm
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Answer:

Step-by-step explanation:

Distance travelled by sound in going to target( insect ) and returning back = 2d ,d is distance of target .

time t = .06 s

speed = distance / time

344.9 = 2d / .06

d = 10.35 m

User Jakewins
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