Answer:
The supermarket should purchase 251 boxes of lettuce tomorrow.
Explanation:
Let X = number of boxes of lettuce that the supermarket should purchase tomorrow
The information provided is:
Cost price per box = $8.00
Selling price per box = $16.00
The amount paid by the dealer for selling old lettuce per box (Salvage price) = $1.80
The mean number of boxes demanded for lettuce is, μ = 245.
The standard deviation of the number of boxes demanded for lettuce is, σ = 38.
Excess cost per box is,
![C_(E)=Cost\ price-Salvage\ price=8.00-1.80=\$6.20](https://img.qammunity.org/2021/formulas/mathematics/college/i0uoi8pco01cxh52wxb36db404izaxsnzr.png)
Shortage cost per box is,
![C_(S)=Selling\ price-Cost\ price=16.00-8.00=\$8.00](https://img.qammunity.org/2021/formulas/mathematics/college/4ce9wgqwy3ojrhsiyx8fj33pael9yr1mur.png)
Compute the level of service as follows:
![Level=(C_(S))/(C_(S)+C_(E))=(8)/(8+6.2)=0.5634](https://img.qammunity.org/2021/formulas/mathematics/college/ka7o3rz38iz8a3pjxt0phaxmnntadc9e8p.png)
For the service level value the z-value is,
z = 0.1596
*Use a z-table.
Compute the value of x as follows:
![z=(x-\mu)/(\sigma)\\0.1596=(x-245)/(38)\\x=245+(0.1596*38)\\x=251.0648\\\approx251](https://img.qammunity.org/2021/formulas/mathematics/college/fkdmwq7ifpbic329962xihehkwmx3lz7sb.png)
Thus, the supermarket should purchase 251 boxes of lettuce tomorrow.