Question

Recall that there is a uniform electric field inside a capacitor. Recall also that in general, LaTeX: V=-\int{\vec{E}\cdot\vec{dl}}V = − ∫ E → ⋅ d l →. In regions of uniform field, this simplifies to LaTeX: V=|\vec{E}|dV = | E → | d, where d is the distance traveled parallel to the electric field. A capacitor with a gap of 0.5 mm has a potential difference from one plate to another of 22 V. What is the magnitude of the electric field within the capacitor? Give your answer in units of kV/m.

Answer 1

E = 44 kV / m

Step-by-step explanation:

In a capacitor the potential difference is

ΔV = -E x

E = - ΔV / x

Let's reduce to the SI system

x = 0.5 mm = 0.5 10⁻³ m

Let's calculate

E = 22 / 0.5 10⁻³

E = 44 10³ V / m

E = 44 kV / m

Note that this electric field is uniform