Question

Ice-skater slides toward a sled sitting on the ice and hits it. The skater exerts a 12.6 N force on the sled at an angle of 15.3° below the horizontal. The sled then moves 15.4 m forward. How much work did the skater do on the sled? Assume friction is negligible.

Knowns Unknown

F = ____________ d = _____________ W = ?

θ = ____________

Solve for the Unknown

a. Write the equation for work
b. Insert known quantities

Answer 1

Expression of work done is

`W = Fd cos\theta`

Work done to move the sled is given as 187.2 J

Step-by-step explanation:

As we know that the formula of work done is given as

`W = Fd cos\theta`

here we know that

F = 12.6 N

d = 15.4 m

`\theta = 15.3 degree`

so we will have

`W = 12.6 * 15.4 cos15.3`

`W = 187.2 J`