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What are the solutions of 4x^2+16x=9

User Bohney
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1 Answer

3 votes

Answer:

Explanation:

Ethan, this is a quadratic equation. We should rewrite this in standard quadratic form: 4x^2 + 16x - 9 = 0. Let's use the quadratic formula approach to solve this:

The coefficients of x are a = 4, b = 16 and c = -9. Thus, the discriminant is

b^2 - 4ac, or 16^2 - 4(4)(-9), or 256 - 144, or 112.

The two solutions are real and are as follows:

-16 ± √112 -16 ± √(16*7) -16 ± 4√7

x = ------------------- = ----------------------- = -----------------

2(4) 8 8

Or, after simplification,

-4 ± √7

x = --------------

2

User Badal
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