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A batch of 479 containers for frozen orange juice contains 3 that are defective. Two are selected, at random, without replacement from the batch. a) What is the probability that the second one selected is defective given that the first one was defective? Round your answer to five decimal places (e.g. 98.76543).

User Cowmoogun
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Answer:

0.00418

Explanation:

The probability of the first one being defected is 3/479, as we have 3 defectives containers in a total of 479 containers.

If the first one is defected and removed, now we have 478 containers, with 2 being defective.

So the probability of the second one being picked being defective, given that the first one was defective, is 2/478 = 1/239 = 0.00418

User Siva Karuppiah
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