Answer:
6 ft
Explanation:
As we know that, the arch meet the ground are the value of x when y = 0
y=−0.9(x+3)(x−3)
<=> 0 = −0.9(x+3)(x−3)
<=> x=3 or x=-3
So we have 2 coordinates: (3, 0) and (-3,0) and the distance between them is:
3 -(-3) = 6
=> The width of the arch at ground level is 6 ft