Answer:
![y\approx 5\ m](https://img.qammunity.org/2021/formulas/physics/college/ya3w8al1cdspkikon008skatawn7is2cmn.png)
Step-by-step explanation:
The pressure of a Fluid
A fluid of density
exerts pressure at a distance y (deep) given by
![P=\rho\cdot y\cdot g](https://img.qammunity.org/2021/formulas/physics/college/2eujj58cb36ucj1fce7d6qy6ursslpvj2r.png)
Where g is the acceleration of gravity or
![g=9.8\ m/s^2](https://img.qammunity.org/2021/formulas/physics/middle-school/m9vkxw5kfxy5atd977mc6kqs9jbuo114kr.png)
This formula computes the pressure assuming the initial pressure is 0 at fluid (water in this case) level.
Knowing the measured pressure, we can know how deep the diver went by solving the equation for y
![\displaystyle y=(P)/(\rho\cdot g)](https://img.qammunity.org/2021/formulas/physics/college/znd9p20w6pbuoc04usr8xe4ssw35z5nd1f.png)
Let's plug in the given values
![P=50,000\ Pa= 50,000\ N/m^2](https://img.qammunity.org/2021/formulas/physics/college/fz7ifyqwc9mjfwiat7cslj8iwbdvpa0d4s.png)
![\rho=1,000\ kg/m^3](https://img.qammunity.org/2021/formulas/physics/college/xoz1vj32tg6re945jq1tjuuzuzvyw66c62.png)
![g=9.8\ m/s^2](https://img.qammunity.org/2021/formulas/physics/middle-school/m9vkxw5kfxy5atd977mc6kqs9jbuo114kr.png)
Thus
![\displaystyle y=(50,000\ N/m^2)/(1,000\ kg/m^3\cdot 9.8\ m/s^2)](https://img.qammunity.org/2021/formulas/physics/college/g3fw25nh4j4wr2wledfaghxjh7rdllphrr.png)
![y\approx 5\ m](https://img.qammunity.org/2021/formulas/physics/college/ya3w8al1cdspkikon008skatawn7is2cmn.png)