The probability of student passing the quiz with at least 50% of the questions correct is 0.62267.
Explanation:
Here, the total number of T/F question = 10
The minimum answers needed correctly answered = 50%
Now, 50% of 10 = 5 questions
So, student needs to answer at least 5 questions correctly.
Here, the possibility of answering a question correctly =
= p = 0.5
Also, the possibility of answering a question wrong =
= q = 0.5
Now, to pass he needs to answer 5 or more ( = 5, 6 , 7 , 8 , 9 or 10) answers correctly.
P(answering 5 correct answer) =
![^(10)C_5(0.5)^5(0.5)^5 =252 (0.5)^(10) = 0.246](https://img.qammunity.org/2021/formulas/mathematics/high-school/8mlu6x88cmyyush0ruvlbo2sn2nle699t1.png)
P(answering 6 correct answer) =
![^(10)C_6(0.5)^6(0.5)^4 =210 (0.5)^(10) = 0.2050](https://img.qammunity.org/2021/formulas/mathematics/high-school/wrlypq7ofbzhi8qoquu92ny57ij48p4tll.png)
P(answering 7 correct answer) =
![^(10)C_7(0.5)^7(0.5)^3 =120 (0.5)^(10) = 0.1171](https://img.qammunity.org/2021/formulas/mathematics/high-school/8bnkkjh9zcybb2xpkk1fiunrpp9jvuahw6.png)
P(answering 8 correct answer) =
![^(10)C_8(0.5)^8(0.5)^2 =120 (0.5)^(10) = 0.0439](https://img.qammunity.org/2021/formulas/mathematics/high-school/9unticx17dxncks4awqegw9ll1l7olvmkl.png)
P(answering 9 correct answer) =
![^(10)C_9(0.5)^9(0.5)^1 = 0.0097](https://img.qammunity.org/2021/formulas/mathematics/high-school/osbpvjuijfvv874q9pe4dstlb3e6ssck6h.png)
P(answering 10 correct answer) =
![^(10)C_(10)(0.5)^7(0.5)^3 =1 (0.5)^(10) = 0.00097](https://img.qammunity.org/2021/formulas/mathematics/high-school/a4reu8ugh7x4afsdw59qo8sz6ioo7gjlbr.png)
So, the total Probability
= (0.246) + (0.2050)+ (0.1171) +(0.0439) + (0.0097) + (0.00097)
= 0.62267 ≈ 62.2 %
Hence, the probability that the student passes the quiz with a grade of at least 50% of the questions correct is 0.62267.