Question

Joshua has (10+6a^2-5a) dollars in his savings account. Maranda had (4a^2a+3) dollars in her saving account how much more money does Joshua have than maranda?

Answer 1

Given Information:

We are given two polynomial equations which represents the amount of savings in dollars

Joshua's savings = 6a² - 5a + 10 dollars

Maranda savings = 4a² + a + 3 dollars (assuming +a since the sign is missing in the question)

Required Information:

How much more money does Joshua have than Maranda = ?

Answer:

Joshua has 2a² - 6a + 7 dollars more than Maranda

Explanation:

We can subtract the amount of savings of Maranda from the amount of savings of Joshua, and we will get the excess amount of savings that Joshua has.

Joshua = 6a² - 5a + 10 dollars

Maranda = 4a² + a + 3 dollars

Excess = 6a² - 5a + 10 - (4a² + a + 3)

change the sign of terms

Excess = 6a² - 5a + 10 - 4a² - a - 3

combine the like terms

Excess = (6a²-4a²) (-5a-a) (+10-3)

Excess = 2a² - 6a + 7

Therefore, Joshua has 2a² - 6a + 7 dollars more than Maranda.

Answer 2

Joshua has 2a^2 -6a + 7 more than Maranda.

Explanation:

Joshua has 6a^2 -5a + 10 dollars and Maranda has 4a^2 + a + 3 to find out how much more money Joshua has we need to subtract the amount he has by the amount of Maranda's account. Since both expressions are pollynomial we'll have to subtract the numbers wich are multiplying the same power, so we do as follow:

6a^2 - 5a + 10 - (4a^2 + a + 3)

6a^2 - 5a + 10 - 4a^2 -a -3

6a^2 - 4a^2 -5a -a + 10 -3

2a^2 -6a + 7

Joshua has 2a^2 -6a + 7 more than Maranda.