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A gas that occupies 50.0 liters has its volume increased to 68 liters when the pressure was changes to 3.0 ATM. What was the original pressure of the gas in ATM?

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Answer:

4.08 atm was the original pressure

Step-by-step explanation:

When the temperature and the number of moles keeps on constant in 2 situations with a gas, we can apply this relation:

P₁ . V₁ = P₂ . V₂

It is an undirectly proportion, When the volume decrease, the pressure increase so if the pressue decrease, the volume will be increased.

P₁ . 50L = 3 atm . 68L

As the volume was increased, the initial pressure must be higher than the final pressure.

P₁ = (3 atm . 68L) / 50L = 4.08 atm

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