Question

Tom's house is located at point (-2, 3) and the school is located at point (-2, -5). What is the distance between Tom's house and the school? Group of answer choices

Answer 1

8 units.

Explanation:

We have been given that Tom's house is located at point (-2, 3) and the school is located at point (-2, -5). We are asked to find the distance between Tom's house and the school.

We will use distance formula to solve our given problem.

`D=√(x_2-x_1)^2+(y_2-y_1)^2)`

Let point
`(-2,3)=(x_1,y_1)` and point
`(-2,-5)=(x_2,y_2)`.

Upon substituting the coordinates of given points in distance formula, we will get:

`D=√((-2-(-2))^2+(-5-3)^2)`

`D=√((-2+2)^2+(-8)^2)`

`D=√(0+64)`

`D=8`

Therefore, the distance between Tom's house and the school is 8 units.