Question

As of a certain​ date, there had been a total of 14,404 performances of two shows on​ Broadway, with 2384 more performances of Show A than Show B. How many performances were there of each​ show?

Answer 1

show A had 8394 performances.

Show B had 6010 performances.

Step-by-step explanation:

Let x represent the number of performances of show A.

Let y represent the number of performances of show B.

As of a certain​ date, there had been a total of 14,404 performances of two shows on​ Broadway. This means that

x + y = 14404 - - - - - - - - - -1

There was 2384 more performances of Show A than Show B. It means that

x = y + 2384

Substituting x = y + 2384 into equation 1, it becomes

y + 2384 + y = 14404

2y = 14404 - 2384

2y = 12020

y = 12020/2

y = 6010

x = y + 2384 = 6010 + 2384

x = 8394

Explanation:

Answer 2

Answer: show A had 8394 performances.

Show B had 6010 performances.

Explanation:

Let x represent the number of performances of show A.

Let y represent the number of performances of show B.

As of a certain​ date, there had been a total of 14,404 performances of two shows on​ Broadway. This means that

x + y = 14404 - - - - - - - - - -1

There was 2384 more performances of Show A than Show B. It means that

x = y + 2384

Substituting x = y + 2384 into equation 1, it becomes

y + 2384 + y = 14404

2y = 14404 - 2384

2y = 12020

y = 12020/2

y = 6010

x = y + 2384 = 6010 + 2384

x = 8394