Answer:
16 colored pencils.
Explanation:
Let x represent the number of pencils that Maurice has.
We have been given that Carl has 4/5 as many color pencils as Maurice, so Carl have
pencils.
We are also told that Samantha has 3/4 as many colored pencils as Carl, so Samantha would have
pencils.
Since have 96 colored pencils altogether, so we will equate sum of all pencils with 96 as:
![x+(4)/(5)x+(3)/(5)x=96](https://img.qammunity.org/2021/formulas/mathematics/high-school/94xpg6h4o0r3niw6t5xwnjsaq3fmli7uem.png)
![(5)/(5)x+(4)/(5)x+(3)/(5)x=96](https://img.qammunity.org/2021/formulas/mathematics/high-school/yg6efw7a359yzgi8mc48j1t5koxnit2875.png)
![(5+4+3)/(5)x=96](https://img.qammunity.org/2021/formulas/mathematics/high-school/ewol377zu1f3w6ttlaykrym9lo4rr6wzhn.png)
![(12)/(5)x=96](https://img.qammunity.org/2021/formulas/mathematics/high-school/8jscazutpqnfxiuxc1rzh95kjyqnzm3c02.png)
![(5)/(12)* (12)/(5)x=96*(5)/(12)](https://img.qammunity.org/2021/formulas/mathematics/high-school/rpj7el1oygqtxsaf312cve46psqu7a8fng.png)
![x=8*5](https://img.qammunity.org/2021/formulas/mathematics/high-school/zdis9qkhii0biw3832zdrnzjvr4el320q7.png)
![x=40](https://img.qammunity.org/2021/formulas/mathematics/middle-school/6q1nrpttldom1ww6h6rt8q3t0qyhd5866u.png)
Now, we will subtract
from x of 40 as:
![x-(3)/(5)x](https://img.qammunity.org/2021/formulas/mathematics/high-school/sp5mlxo0ajllcktocw0sw9no55fp3a2z2u.png)
![40-(3)/(5)(40)](https://img.qammunity.org/2021/formulas/mathematics/high-school/i5ii71z7yok5qhsc68ny2ro9izqlvqdy1f.png)
![40-3(8)](https://img.qammunity.org/2021/formulas/mathematics/high-school/i83vlq4z44aunxa5tkvi9fkgpgemqskw38.png)
![40-24=16](https://img.qammunity.org/2021/formulas/mathematics/high-school/yoqtopeim4vottkh3zun77hhnh3jn4ue3p.png)
Therefore, Samantha has 16 fewer colored pencils than Morris.