Question

A survey among US adults of their favorite toppings on a cheese pizza reported that 43% favored pepperoni, 14% favored mushrooms, and 6% favored both pepperoni and mushrooms. What is the probability that a random adult favored pepperoni or mushrooms on their cheese pizza? Provide your answer as a whole number in the box below, i.e., .32 is 32% so you would enter 32. Round as needed.

Answer 1

51% of US adults favored pepperoni or mushrooms on their cheese pizza.

Explanation:

We are given the following in the question:

Percentage of US adults that favored pepperoni = 43%

`P(P) = 0.43`

Percentage of US adults that favored mushroom = 14%

`P(M) = 0.14`

Percentage of US adults that favored both pepperoni and mushroom = 6%

`P(M\cap P) = 0.06`

We have to evaluate the probability that a random adult favored pepperoni or mushrooms on their cheese pizza.

Thus, we have to evaluate:

`P(M\cup P) = P(M) + P(P) - P(M\cap P)\\P(M\cup P) = 0.43 + 0.14 - 0.06\\P(M\cup P) = 0.51 = 51\%`

Thus, 51% of US adults favored pepperoni or mushrooms on their cheese pizza.