Question

Un observador se acerca con una velocidad de 15m/s a un parlante estático que está emitiendo un sonido con una frecuencia de 297 Hz. ¿Cuál es la frecuencia percibida por el observador?

Answer 1

310 Hz

Explanation:

This is a spanish language mathematical question.

We translate this to english:

An observer approaches a static speaker at 15 meters per second. The speaker is emitting a sound with a frequency of 297 Hz. What is the frequency perceived by the observer?

Solution:

This can be solved using doppler effect formula. Which is:

`f=((c)/(c+V_s))f_0`

Where

f is the observed frequency (297 Hz)

c is the speed of sound (343 m/s)

`V_s` is the velocity of source (given as 15)

`f_0` is what we want to find

Now, substituting, we solve:

`f=((c)/(c+V_s))f_0\\297=((343)/(343+15))f_0\\297=(0.9581)f_0\\f_0=309.99`

Rounding,

We can say the perceived frequency would be around 310 Hz