Question

The height of a helicopter above the ground is given by h 5 3.00t3, where h is in meters and t is in seconds. At t 5 2.00 s, the helicopter releases a small mailbag. How long after its release does the mailbag reach the ground

Answer 1

The mailbag reaches the ground instantaneously after its release.

Step-by-step explanation:

The height of the helicopter above the ground is given by the equation h = 3.00t^3, where h is the height in meters and t is the time in seconds. When t = 2.00 s, the helicopter releases a small mailbag. To find how long it takes for the mailbag to reach the ground, we need to find the time when the height is equal to 0.

Setting h = 0, we have 3.00t^3 = 0. Solving this equation, we find that t = 0 s. Therefore, the mailbag reaches the ground instantaneously after its release.