Question

X^2-16/(x+4)(x-5) x=-4 x=1 continuous at x=-4?

Answer 1

Yes, its continuous

Explanation:

We use the formula:

x^2-y^2=(x-y)(x+y),

And we know that 16=4^2, so we have:

`(x^2-16)/((x+4)(x-5))=((x-4)(x+4))/((x+4)(x-5))=(x-4)/(x-5)`

So for x=-4 we have -8/-9,i.e, it is 8/9, so it is continuous.

I dont know what is x=1, because for x=1 the function has value 3/4.

But function is not continuous in x=5 becaus for that x we will get 1/0, and that is not definite.

:)