Register
20cm³ of sulphuric acid reacts completely with excess zinc to form 0.1 mole of hydrogen gas. Calculate the molarity of the acid used.​
3.3k views
0 votes
20cm³ of sulphuric acid reacts completely with excess zinc to form 0.1 mole of hydrogen gas. Calculate the molarity of the acid used.​

User MD TAREQ HASSAN
by
3.6k points

1 Answer

3 votes

Answer:

20cm³ of sulphuric acid reacts completely with excess zinc to form 0.1 mole of hydrogen gas. Calculate the molarity of the acid used.?

Molarity= mol/volume

Molarity= 0.1/20

Molarity= 0.005mol/L

Step-by-step explanation:

User Adam Mills
by
4.0k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

4.4m questions

5.7m answers

Other Questions

What is the variable for this number 22.4L?
Which of the following aqueous solutions are good buffer systems? . 0.29 M perchloric acid + 0.15 M potassium perchlorate 0.16 M potassium acetate + 0.26 M acetic acid 0.18 M hydrofluoric acid + 0.12 M
Suppose a flask is filled with of , of and of . The following reaction becomes possible: The equilibrium constant for this reaction is at the temperature of the flask. Calculate the equilibrium molarity
What mass of 2-naphthol would have to be ingested by each rat in a sample set of rats in order to kill half the population of rats? Assume each rat weighs 230 g. Show your calculations for full credit.
A helium balloon containing 0.100 mol of gas occupies a volume of 2.4 L at 25 C and 1.0 atm. how many moles have we added if we inflate it to 5.6 L?
Link Copied!