Question

M1 = 3 kg, v1= < 10, -5, 13 > m/s m2 = 2 kg, v2= < -15, 7, -4 > m/s m3 = 3 kg, v2= < -28, 37, 25 > m/s what is total kinetic energy?

Answer 1

Step-by-step explanation:

Here, the three components of velocity of each of the masses are provided.

The net velocity of each of three masses are:

`v_(1) = \sqrt{v_(11)^(2) +v_(12)^(2) + v_(13)^(2)} = √(294) = 17.15 m/s`

Similarly,

v2 = 17.03 m/s

v3 = 52.71 m/s

Since kinetic energy is a scalar quantity, there will be no vectorial considerations involved.

`KE = (1)/(2)m_(1)v_(1)^(2) + (1)/(2)m_(2)v_(2)^(2) + (1)/(2)m_(3)v_(3)^(2)`

Net Kinetic Energy = 4898.72 J