The question is incomplete, here is the complete question:
The hydrolysis of sucrose into glucose and fructose in acidic water has a rate constant of 1.8×10⁻⁴ s⁻¹ at 25°C. Assuming the reaction is first order in sucrose, determine the mass of sucrose that is hydrolyzed when 2.65 L of a 0.120 M sucrose solution is allowed to react for 200 min.
Answer: The mass of sucrose solution left is 12.56 grams
Step-by-step explanation:
Molarity is calculated by using the equation:

Molarity of sucrose solution = 0.120 M
Volume of solution = 2.65 L

Rate law expression for first order kinetics is given by the equation:
![k=(2.303)/(t)\log([A_o])/([A])](https://img.qammunity.org/2021/formulas/chemistry/college/bbi6c2ny1tf8wlzntta3i570f6pal714ld.png)
where,
k = rate constant =

t = time taken for decay process = 200 min = (200 × 60) = 12000 seconds
= initial amount of the sample = 0.318 moles
[A] = amount left after decay process = ?
Putting values in above equation, we get:
![1.8* 10^(-4)=(2.303)/(12000)\log(0.318)/([A])](https://img.qammunity.org/2021/formulas/chemistry/college/5wcykp1ol8anumylv8p03l1aqp2tpndreo.png)
![[A]=0.0367mol](https://img.qammunity.org/2021/formulas/chemistry/college/ihbijmfaqhh6qw1carwu9aqh732q9capyv.png)
To calculate the mass from given number of moles, we use the equation:

Moles of sucrose = 0.0367 moles
Molar mass of sucrose = 342.3 g/mol
Putting values in above equation, we get:

Hence, the mass of sucrose solution left is 12.56 grams