Question

2 C2H6 + 7 O2 → 4 CO2 + 6 H2O

how many moles of ethane (C2H6) are required to produce 13.5 moles of water from the above reaction?

Answer 1

Balanced Eqn

2

C

2

H

6

+

7

O

2

=

4

C

O

2

+

6

H

2

O

By the Balanced eqn

60g ethane requires 7x32= 224g oxygen

here ethane is in excess.oxygen will be fully consumed

hence

300g oxygen will consume

60

⋅

300

224

=

80.36

g

ethane

leaving (270-80.36)= 189.64 g ethane.

By the Balanced eqn

60g ethane produces 4x44 g CO2

hence amount of CO2 produced =

4

⋅

44

⋅

80.36

60

=

235.72

g

and its no. of moles will be

235.72

44

=5.36 where 44 is the molar mass of Carbon dioxideBalanced Eqn

2

C

2

H

6

+

7

O

2

=

4

C

O

2

+

6

H

2

O

By the Balanced eqn

60g ethane requires 7x32= 224g oxygen

here ethane is in excess.oxygen will be fully consumed

hence

300g oxygen will consume

60

⋅

300

224

=

80.36

g

ethane

leaving (270-80.36)= 189.64 g ethane.

By the Balanced eqn

60g ethane produces 4x44 g CO2

hence amount of CO2 produced =

4

⋅

44

⋅

80.36

60

=

235.72

g

and its no. of moles will be

235.72

44

=5.36 where 44 is the molar mass of Carbon dioxide

Step-by-step explanation:

Answer 2

x = 4.5

4.5 moles of C2H6 is required to produce 13.5 moles of H2O

Step-by-step explanation:

Given equation is :

2 C2H6 + 7 O2 → 4 CO2 + 6 H2O

if it requires 2 moles of C2H6 to produce 6 moles of H2O

then x moles of C2H6 is required to produce 13.5 moles of H2O

Using unitary method for solving, we get

x = 13.5 x 2 / 6

x = 13.5 / 3

x = 4.5

Therefore, 4.5 moles of C2H6 is required to produce 13.5 moles of H2O