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*100 points* What is the value of x in these polygons?

*100 points* What is the value of x in these polygons?-example-1
User Wes Winder
by
4.8k points

2 Answers

4 votes

Answer and Step-by-step explanation:


Greetings!


Let's~answer~your~question!


Since~ we~ know~ that ~these ~two~ are~ similar, ~it ~is ~also~ given ~that~ corresponding\\ parts ~of ~the~ triangle~ are ~proportional.~ In ~result,~ you~ can~ set~ the~ proportions~\\something~ like~ this:


(16)/(32)= (12)/(24)


Now,~from~ here, you~ can ~figure~ out~ that~ the~ ratio~ of ~the ~larger ~triangle~ to ~the \\~smaller~ triangle~ is ~.75:1


You~can~ then~ apply~ this~ to~ the~ side ~of ~x-1 ~and ~set~ up ~the~ equation.


.75(x-1)=6


Now,~solving~ the~ equation,~ you~ get~ x=9.~ Substitute~ that~ into~ x-1~ and~ you\\ get~ 8 ~as ~that~ side~ length.~ To~ check, compare:


(8)/(6)=(32)/(24)


Thus,~the~value~of~x~is=9.


Hope~my~answer~helps~you!~Have~a~blessed~day~ahead!


-Isabelle~Williams

User Pixelworlds
by
5.3k points
2 votes

Answer:


x = 9

Explanation:

Step 1: Make an expression


(x-1)/(16) = (6)/(12)

Step 2: Cross multiply


(x-1)/(16) = (6)/(12)


12(x-1) = 6*16

Step 3: Distribute


12(x-1) = 6*16


(12*x)+(12*-1) = 96


12x - 12 = 96

Step 4: Add 12 to both sides


12x - 12 + 12 = 96 + 12


12x = 108

Step 5: Divide both sides by 12


12x / 12 = 108 / 12


x = 9

Answer:
x = 9

User Katharina
by
4.9k points