Question

The mass on a spring has a mass of 1.25 kg. If the spring constant is 250 N/m, what is the period of the mass spring system? What is the frequency? [0.44 s, 2.3 Hz]

Answer 1

The time period is 0.44s and frequency is 2.3 Hz

Step-by-step explanation:

The time period of spring T = 2π
`\sqrt{(m)/(k) }`

here m is the mass with the spring

K is the spring constant

Thus T = 2π
`\sqrt{(1.25)/(250) }` =
`(\pi √(2) )/(10)` = 0.43 sec

The frequency =
`(1)/(T)` =
`(1)/(0.43)` = 2.3 Hz