Question

A height of 26 feet and a diameter of 5.6 feet. What is the volume of the geode, rounded to the nearest tenth?

Answer 1

Therefore,

The volume of the geode, rounded to the nearest tenth is 640.1 feet³.

Explanation:

Given:

Geode shaped approximately like a cylinder. such that

Height = h = 26 feet

Diameter = d = 5.6 feet

`Radius = r =(d)/(2)=(5.6)/(2)=2.8\ feet`

To Find:

volume of the geode = ?

Solution:

Geode shaped approximately like a cylinder,

So, Volume of Cylinder is given by,

`\textrm{Volume of Cylinder}=\pi r^(2)h`

Where,

Height = h

Radius = r

pi = 3.14

Substituting the values we get

`\textrm{Volume of Cylinder}=3.14* 2.8^(2)* 26=640.05\approx 640.1\ feet^(3)`

Therefore,

The volume of the geode, rounded to the nearest tenth is 640.1 feet³.