Answer:
Step-by-step explanation:
a)
Find the truck load time using relation
load time = Truck capacity/Shovel production
Substitute 12 BCY for truck capacity and 300 BCY/h for shovel production
load time = (12 BCY)/(300 BCY/h)=0.04h=0.04 x 60min=2.4min
Find the truck cycle time using relation
Truck cycle time = Load time + Travel + Fixed cycle time
Substitute 2.4 min for load time 8 min for travel time and 2 min for fixed cycle time
Truck cycle time = 2.4 + 8min + 2 min = 12.4 min
Find the number of trucks required using relation
Number of trucks = Truck cycle time/Load time
Substitute 12.4 min for truck cycle time and 2.4 min for load time
Number of trucks = 12.4/2.4=5.2=6
Therefore, the theoritical number of trucks required is 6
b)
Find the expected production using the relation
Production = shovel production (BCM/h) x Job efficiency
Substitute 300 BCY/h for shovel production and 0.80 for job efficiency
Production = 300 BCY/h x 0.80 = 240 BCY/h
Therefore, the expected production is 240 BCY/h
c)
Find the total cost of equipment per hour using relation
Total cost per hour = cost of shovel per hour + cost of 6 trucks per hour
Substitute $40 for cost of shovel per hour and $20 for cost of one truck per hour
Total cost = $40 + (6 x $20) = $160
calculate the unit cost of loading and hauling using relation
Unit cost loading and hauling = Equipment cost per hour/Equipment production per hour
Substitute $160 for the total equipment cost per hour 183.2 BCM/h for equipment production per hour
unit cost loading and hauling = $160/(240 BCY/h)=$0.667 BCY
Therefore, the uniy cost of loading and hauling is $0.667 BCY