Question

The length of a rectangle is 5 yd longer than its width.

If the perimeter of the rectangle is 30 yd, find its area,

Answer 1

Area of the rectangle is 36 yd²

Explanation:

• Step 1: Let width of the rectangle be x yd. So, length = 5 + x. Perimeter = 30 yd.

Perimeter = 2 (length + width)

30 = 2 (x + 5 + x)

30 = 10 + 4x

4x = 20

x = 4

∴ 5 + x = 9

⇒ Length = 9 yd and width = 4 yd

• Step 2: Find area

Area = length ××width

= 9 × 4 = 36 yd²