Question

If the heat of combustion for a specific compound is − 1160.0 kJ / mol and its molar mass is 74.23 g / mol, how many grams of this compound must you burn to release 264.90 kJ of heat?

Answer 1

16.95 grams of this compound must be burn to release 264.90 kJ of heat.

Step-by-step explanation:

The heat of combustion of a compound =
`\Delta H_(comb)=-1160.0 kJ/mol`

Suppose n moles of compound on combustion gives Q amount of energy

Q = -264.90 kJ

`n* \Delta H_(comb)=Q`

`n=(Q)/(\Delta H_(comb))=(-264.90 kJ)/(-1160.0 kJ/mol)=0.2284 mol`

Mass of 0.2284 moles of compound = m

Molar mass of compound = M = 74.23 g/mol

`m=n* M=0.2284 mol* 74.23 g/mol=16.95 g`

16.95 grams of this compound must be burn to release 264.90 kJ of heat.