Question

When aluminum is placed in concentrated hydrochloric acid, hydrogen gas is produced. 2 Al ( s ) + 6 HCl ( aq ) ⟶ 2AlCl3 ( aq ) + 3 H 2 ( g ) What volume of H 2 ( g ) is produced when 8.60 g Al ( s ) reacts at STP

Answer 1

The answer to your question is V = 19.9 L

Step-by-step explanation:

Data

mass of Al = 8.60 g

volume of H₂ = ?

Balanced chemical reaction

2Al + 6HCl ⇒ 2AlCl₃ + 3H₂

1.- Use proportions to calculate the mass of H₂ produced

Atomic mass of Al = 2 x 27 = 54 g

Atomic mass of H₂ = 6 x 1 = 6 g

54 g of Al -------------------- 6 g of H₂

8 g of Al ------------------- x

x = (8 x 6) / 54

x = 48 / 54

x = 0.89 g of H₂

2.- Calculate the volume of H₂

- Convert the H₂ to moles

1 g of H₂ --------------- 1 mol

0.89 g ---------------- x

x = 0.89 moles

1 mol of H₂ -------------- 22.4 l

0.89 moles ------------- x

x = (0.89 x 22.4) / 1

x = 19.9 L