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A red sports drink contains Red 40 dye. A 5.4 mL aliquot of this sports drink was diluted to 25.0 mL with deionized water in a volumetric flask to form a dilute drink solution. The concentration of Red 40 dye in the dilute solution was determined to be 18.1 ppm from the calibration plot. What is the concentration of Red 40 dye (ppm) in the original sports drink

User Joald
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Answer:

84.0 ppm is the concentration of Red 40 dy in the original sports drink.

Step-by-step explanation:

Concentration of red dye in sport drink before dilution
C_1=?

Volume of the sport drink before dilution
V_1=5.4 mL

Concentration of red dye in sport drink after dilution
C_2=18.1 ppm

Volume of the sport drink after dilution
V_2=25.0 mL


C_1V_1=C_2V_2( dilution )


C_1=(C_2V_2)/(V_1)=(18.1 ppm* 25.0 mL)/(5.4 mL)


C_1=83.80 ppm\approx 84.0ppm

84.0 ppm is the concentration of Red 40 dy in the original sports drink.

User Bokor
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