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7. A wall of length 10 m was to be built across an open

ground. The height of the wall is 4 m and thickness of
the wall is 24 cm. If this wall is to be built up with
bricks whose dimensions are 24 cm x12 cm x 8 cm,
how many bricks would be required?

User Shadonar
by
3.6k points

1 Answer

3 votes

Answer:

4167 bricks

Explanation:

We first find the amount of space the wall will occupy by multiplying the dimensions given, is that;

=10m×4m×8cm

But 8cm=0.08m

This implies that,

10m×4m×8cm

=10m×4m×0.08m


= 9.6 {m}^(3)

The dimensions of each brick that will be used is 24 cm x12 cm x 8 cm.

We calculate the space each brick will occupy

This implies;

24 cm x12 cm x 8 cm

Converting to meters we obtain

0.24m x 0.12m x 0.08m


=2.304 *{10}^( - 3){m}^(3)

To get the number of bricks that will be required, we divide 9.6 meters cube by


2.304 * {10}^( - 3){m}^(3)


\implies \frac{9.6}{2.304 * {10}^( - 3)} = 4166.667

Approximately, 4167 bricks will be required.

User Sleepynate
by
2.8k points