Question

At an air show a jet flies directly toward the stands at a speed of 1190 km/h, emitting a frequency of 3580 Hz, on a day when the speed of sound is 342 m/s. What frequency (in Hz) is received by the observers?

Answer 1

The received frequency by the observers is 106.46 kHz.

Step-by-step explanation:

Given that,

Speed = 1190 km/h = 330.5 m/s

Frequency = 3580 Hz

Speed of sound = 342 m/s

We need to calculate the received frequency by the observers

Using formula of frequency

`f'=f((v+v_(o))/(v-v_(s)))`

Where, f = frequency

`v_(o)` =velocity of observer

`v_(s)` = velocity of source

Put the value into the formula

`f'=(342+0)/(342-330.5)*3580`

`f'=106.46\ kHz`

Hence, The received frequency by the observers is 106.46 kHz.