Answer:
a. -10.8kgm/s
b. 1542.86kgm/s^2 or 1.52kN
Step-by-step explanation:
a. Given initial velocity
, final velocity
, duration of collision as 0.007s and the mass as
, the impulse on the hand can be calculated as:

Hence the impulse on the hand is -10.8 kgm/s
b. From a above we know the impulse on the hand as -10.8 kgm/s and the duration of the impulse as 0.007s:
-We use these values to calculate the average force on the hand:

Hence the average force on the hand is 1542.86kgm/s^2 or 1.52kN