Question

2=x^2-10x solve by completing the square

Answer 1

`2=x^2-10x\\\\\implies x^2 -10x =2\\\\\implies x^2 -2\cdot 5 x +5^2 -5^2 = 2\\\\\implies x^2 -2\cdot 5x +5^2 = 2+5^2 \\\\\implies (x-5)^2 = 27\\\\\implies x-5 = \pm\sqrt {27}\\\\\implies x = \pm√(27) +5=\pm3√(3)+5\\\\\text{Hence,}~ x = 5+3\sqrt 3~\text{or}~ x = 5-3\sqrt 3`