Question

This problem has been solved! See the answer A kayaker paddles with a power output of 60.0 W to maintain a steady speed of 1.40 m/s a.)Calculate the resistive force exerted by the water on the kayak. b.) If the kayaker doubles her power output, and the resistive force due to the water remains the same, by what factor does the kayaker's speed change?

Answer 1

a) Resistive force = 42.9 N

b) The speed doubles!!

Step-by-step explanation:

Power = (Energy/time) = (F.d/t) = F.v

a) P = F.v

P = 60.0 W

F = ?

v = 1.40 m/s

60 = F (1.4)

F = (60/1.4)

F = 42.9 N

b) If power doubles, P = 120.0 W and F stays the same, F = 42.9 N

P = F.v

v = (P/F)

v = (120/42.9)

v = 2.80 m/s.

The speed doubles.