Question

Could you help plz.​

Answer 1

Cost of each bags of flour = $2.50

Cost of each bags of butter = $3.75

Solution:

Let f be the bags of flour and b be the pounds of butter.

Cost of 20 bags of flour 16 pound of butter = 110

⇒ 20f + 16b = 110 -------------------- (1)

Cost of 30 bags of flour 12 pound of butter = 120

⇒ 30f + 12b = 120 -------------------- (2)

Equation (1) and (2) are the system of equations.

(2) ⇒ 30f + 12b = 120

Subtract 30f from both sides.

⇒ 12b = 120 – 30f

Divide by 12 on both sides.

`$\Rightarrow b =(120-30f)/(12)` -------------------- (3)

Substitute (3) in (1).

`$20f+16\left((120-30f)/(12)\right)=110`

`$20f+4\left((120-30f)/(3)\right)=110`

`$20f+4(40-10f)=110`

`$20f+160-40f=110`

Subtract 160 from both sides.

`$-20f=-50`

Divide by –20, we get

`$f=(5)/(2)`

f = 2.50

Substitute f = 2.5 in equation (3), we get

`$\Rightarrow b =(120-30(2.50))/(12)`

`$b=(15)/(4)`

b = 3.75

Cost of each bags of flour = $2.50

Cost of each bags of butter = $3.75