Answer:
-2.35 kJ
Step-by-step explanation:
The energy change of the NI3 sample, ΔE = Q + W. where Q = quantity of heat and W = workdone. After decomposing to form nitrogen gas and iodine gas, 3.30 kJ of heat is released, Q = -3.30 kJ and since the sample does work of 950 J, W = +950 J = + 0.950 kJ.
ΔE = Q + W = -3.30 kJ + (+ 0.950 kJ) = -3.30 kJ + 0.950 kJ = -2.35 kJ