192k views
0 votes
The largest taco contained approximately 1 kg of onion for every 6.8 kg grilled steak. The total weight of these two ingredients was 617.6 kg. How many kilograms of each ingredient were used?

User Vcs
by
7.2k points

2 Answers

3 votes

Answer:

Explanation:

For a taco:

Ingredient:

1 kg of onion for every 6.8 kg grilled steak

Wt = 617.6 kg

Let x = mass of onion and y = mass of grilled steak

x + 6.8y = 617.6

Can also be written as:

x + 6.8x = 617.6

x = 617.6/7.8

= 79.2.

User Perazzo
by
7.1k points
3 votes

Answer: Onion = 79.17 kg

Grilled steak = 538.356 kg

Explanation:

Hi, to answer this question we have to write an equation with the information given:

1 k + 6.8 k = 617.6

Where “k” is a constant value, a multiplier.

Solving for k:

7.8 k = 617.6

k = 617.6 /7.8

k= 79.17

So:

Amount of onion used:

1 (79.17) = 79.17 kg

Amount of grilled steak used:

6.8 (79.17) = 538.356 kg

Feel free to ask for more if needed or if you did not understand something.

User Trinadh Thatakula
by
6.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.