Question

Solve the following quadratic by completing the square.

f(x) = x2 – 20x + 41

Answer 1

`x=\left \{ {{10+√(59)} \atop {10-√(59)}} \right.`

Explanation:

`x^2-20x+41=0`

`(x-10)^2-10^2+41=0`

`(x-10)^2-59=0`

`(x-10)^2=59`

`(x-10)=\left \{ {{√(59)} \atop {-√(59)}} \right`

`x=\left \{ {{10+√(59)} \atop {10-√(59)}} \right.`