Answer:
x = 2 , y = 1
Explanation:
to solve this simultaneous equation, we say
let
6x - 2y = 10 ..................... equation 1
6x + 3y = 15 ........................ equation 2
using substitution method
from equation 1
6x - 2y = 10 ..................... equation 1
6x = 10 + 2y
divide both sides by 6
x = (10 + 2y)/6 ......................... equation 3
put the value of x in equation 2
6x + 3y = 15 ........................ equation 2
6[( 10 + 2y)/6] + 3y = 15
10 + 2y + 3y = 15
collect the like terms
2y + 3y = 15 - 10
5y = 5
divide both sides by 5
we have
y = 1
put y = 1 in equation 3 to get the value of x
x = (10 + 2y)/6 ......................... equation 3
x = 10 + 2(1) /6
x = 12/6
x = 2
therefore the value of x and y is 2 & 1 respectively